[5.02] 16 < 2x + 4 < 4 can someone help me solve. (Without giving the answer).
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jimthompson5910 (jim_thompson5910):
Similar example
-22 < 2x + 6 < 14
-22-6 < 2x + 6 -6< 14-6 ... Subtract 6 from all sides.
-28 < 2x < 8 ... Combine like terms.
-28/2 < 2x/2 < 8/2 ... Divide all sides by 2.
-14 < x < 4 ... Reduce
So the solution is
-14 < x < 4
Note: this is NOT the answer to your problem since this is a similar example problem
OpenStudy (anonymous):
16<2x+4<4
16-4 < 2x+4-4 < 4-4
12 < 2x
12/2 < 2x/2
6 < x
Is this correct?
jimthompson5910 (jim_thompson5910):
what happened on step 3?
jimthompson5910 (jim_thompson5910):
and is that 16 really positive?
OpenStudy (anonymous):
do i make the 16 negative or is it positive in the original question?\
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jimthompson5910 (jim_thompson5910):
i'm just asking if 16 is positive in the original question
jimthompson5910 (jim_thompson5910):
or is it negative?
OpenStudy (anonymous):
yes it is positive.
jimthompson5910 (jim_thompson5910):
ok, it might make it easier if we let
z = 2x+4
so
16 < 2x + 4 < 4
is the same as
16 < z < 4
jimthompson5910 (jim_thompson5910):
do you see a problem here?
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OpenStudy (anonymous):
not really
jimthompson5910 (jim_thompson5910):
z is some number
so
16 < z < 4
says
16 < some number < 4
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
see the problem now?
OpenStudy (anonymous):
the z or some number.
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OpenStudy (anonymous):
??
jimthompson5910 (jim_thompson5910):
16 < z < 4
says
"z is some number between 16 and 4....ie, its greater than 16 AND less than 4 at the same time"
see the problem now?
OpenStudy (anonymous):
sorta
jimthompson5910 (jim_thompson5910):
can you name any numbers that are greater than 16 AND less than 4 at the same time?
OpenStudy (anonymous):
ummm well wouldnt you have to graph both starting at 4 shading right and 16 shading left.
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OpenStudy (anonymous):
im not good at inequalitys at all
jimthompson5910 (jim_thompson5910):
think of a number greater than 16
OpenStudy (anonymous):
17
jimthompson5910 (jim_thompson5910):
is that less than 4?
OpenStudy (anonymous):
nope
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jimthompson5910 (jim_thompson5910):
what about 18?
OpenStudy (anonymous):
stilll over
jimthompson5910 (jim_thompson5910):
and 19?
OpenStudy (anonymous):
still over
jimthompson5910 (jim_thompson5910):
so are there any numbers that are greater than 16 and less than 4?
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OpenStudy (anonymous):
no
jimthompson5910 (jim_thompson5910):
so
16 < z < 4
is not possible, agreed?
OpenStudy (anonymous):
agreed
jimthompson5910 (jim_thompson5910):
by extension
16 < 2x+4 < 4
is also not possible
jimthompson5910 (jim_thompson5910):
since z = 2x+4
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OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
so there are no numbers that can replace 'x' and make
16 < 2x+4 < 4
a true inequality
OpenStudy (anonymous):
ok
jimthompson5910 (jim_thompson5910):
does that make sense?
OpenStudy (anonymous):
well yes because oof the 16 and 4 part
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