Just testing to see if I've memorized this formula again: $$\text{Sum of the factors of a number: }\frac{a^{p + 1} - 1}{a - 1} \times \frac{b^{q + 1} - 1}{b - 1} \times \frac{c^{r + 1} - 1}{c - 1}...$$where a, b, and c are prime factors of the given number and where p, q, and r are exponents relating to the multiplicity of the prime factors. Is it correct?

Question

experimentx · Answer

hmm... i never seen this ... could you elaborate?

anonymous · Answer

For instance, if we were given the number 12, and you prime factor it:
$$12 = 2^2 \times 3$$Then a would be 2, p would be 2, b would be 3, and q would be 1.

anonymous · Answer

Then the sum of the factors would be 2 + 2 + 3 = 7. I think the formula is a spinoff of the number of factors formula, but I'm trying to see if I have completely got this formula down.

experimentx · Answer

so it would be |dw:1344116637049:dw|