evaluate using l'hopital
i know you can't use l'hopital unless it is in the form of 0/0 or inf/inf. how can i transform this into one of those forms

Question

evaluate using l'hopital
i know you can't use l'hopital unless it is in the form of 0/0 or inf/inf. how can i transform this into one of those forms

anonymous · Answer

$$\lim_{x \rightarrow (\pi/2)+} \tan x- \sec x$$

lgbasallote · Answer

$$\tan x - \sec x \implies \frac{\sin x}{\cos x} -\frac{1}{\cos x} \implies \frac{\sin x - 1}{\cos x}$$
does that help?

dumbcow · Answer

that should work

anonymous · Answer

yes soo much. So whenever I have a function such as this, the best thing to do is to convert to sin and cos?

lgbasallote · Answer

yup. always

anonymous · Answer

thanks, appreciate it!

lgbasallote · Answer

welcome ^_^

anonymous · Answer

the final answer is 0, just checking?

lgbasallote · Answer

why do you say so?

anonymous · Answer

because after finding the derivatives of num I got 0 and den i got -1. 0/-1 = 0

lgbasallote · Answer

but before you derive you need to verify it's 0/0 or infinity/infinity right? is this in that form?