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Mathematics 15 Online
OpenStudy (anonymous):

how to simplify

OpenStudy (anonymous):

\[\frac{\log_3{12}\times \log_4{12}}{\log_3{12}+\log_4{12}} \]

OpenStudy (jiteshmeghwal9):

i can't understand this question which property will come into use :(

OpenStudy (jiteshmeghwal9):

a very tilting question

OpenStudy (jiteshmeghwal9):

\[\frac{\log_{3}12}{\log_{3}{12}+\log_4{12}}\times \log_4{12}\]

OpenStudy (anonymous):

um if you put in calculator its 1.. or do i need to use differents bases to simplify by hand

OpenStudy (jiteshmeghwal9):

wait lemme find a property to solve this question

OpenStudy (jiteshmeghwal9):

@mathslover is there any property something like this\[\log_{a}{b}+\log_{c}{b}=\log_{ac}{b}\]????????

OpenStudy (saifoo.khan):

\[\log_a b \times \log_a c = \log_a (b\times c)\]change of base.

OpenStudy (saifoo.khan):

Ops! That's a positive in b/w on the left side.

OpenStudy (saifoo.khan):

\[\log_a b + \log_a c = \log_a(b\times c)\]

mathslover (mathslover):

\[\large{\cfrac{\frac{1}{\log_{12}{3}}*\frac{1}{\log _{12}4}}{\frac{1}{\log_{12}3}+\frac{1}{log_{12}4}}}\]

mathslover (mathslover):

always remember that: \[\large{\log_ab=\frac{1}{\log_ba}}\]

mathslover (mathslover):

can u solve further @powerangers69 @jiteshmeghwal9 dude this is the correct way

OpenStudy (jiteshmeghwal9):

k!

OpenStudy (jiteshmeghwal9):

sorry! i forgot the change of base

mathslover (mathslover):

no problem ... we can further conclude and we will get the answer as 1

OpenStudy (anonymous):

thanks!!

OpenStudy (rsadhvika):

alternative \( \frac{\ln 12/ \ln 3 * \ln 12/ \ln 4} {\ln 12/ \ln 3 + \ln 12 / \ln 4}\) \( \frac{\ln 12 * \ln 12}{\ln 12 * \ln 4 + \ln 12 * \ln 3}\) \( \frac{\ln 12 * \ln 12}{ \ln 12 ( \ln 4 + \ln 3) } \) \(\frac{\ln 12}{(ln 4 + ln 3)}\)

mathslover (mathslover):

welcome and best of luck

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