Question

Simplify: (5x+6)/(x^2-1) - (1)/(x^2-1)

Answer 1

just take the base in common and you'll get the solution

Answer 2

so take out (x^2-1) ?

Answer 3

yes...

Answer 4

so what would it be then?

Answer 5

now you'll have (5x+6-1)/(x^2-1)

Answer 6

simplify it ...now

Answer 7

and take out 5 in common from numerator and factorize the denominator

Answer 8

i dont know what to do at all...

Answer 9

\[\large{\frac{5x+6}{x^2-1}-\frac{1}{x^2-1}}\]
\[\large{\frac{5x+6-1}{x^2-1}}\]
right?

Answer 10

yeah, but wht next?

Answer 11

what is 6 - 1 ?

Answer 12

would it be 5/x-1 ?

Answer 13

5

Answer 14

very good now :
\[\large{\frac{5x+6-1}{x^2-1}}\]
\[\large{\frac{5x+5}{x^2-1}}\]

Answer 15

no it would be 5(x+1)/(x+1)(x-1) now you'll get 5/(x-1)

Answer 16

\[\large{\frac{5(x+1)}{(x+1)(x-1)}}\]
\[\large{\frac{5\cancel{(x+1)}^1}{\cancel{(a+1)}^1(a-1)}}\]
\[\large{\frac{5}{x-1}}\]

Answer 17

oops sorry i meant x-1 there not a-1

Answer 18

so got it @simplybeyoutiful ?

Answer 19

yes, thats what i thought it was thank you

Answer 20

ur welcome