Question

A circle has the following equation as shown below

Which statement is true for the circle?


Its center is at (-1, 5/4), and the radius is 7/3 .

Its center is at (-1, 5/4), and the radius is 49/9.

Its center is at (1, -5/4), and the radius is 49/9.

Its center is at (1, -5/4), and the radius is 7/3.

Answer 1

@satellite73

Answer 2

So the trick here is that when you include the origin in your equation, you change the sign.
An origin at x = 5 has a minus 5 in the equation. Same for y. HTH

Answer 3

So , would i substitute 5 in for x. in the equation?

Answer 4

@jim_thompson5910

Answer 5

Hint:

The circle

\[\Large (x-h)^2+(y-k)^2=r^2\]

has the center (h,k) and has a radius of 'r'

Answer 6

@jim_thompson5910

I cant get it, i've plugged every thing in, and nothing will work

Answer 7

It might help to rewrite x+1 as x-(-1)

Answer 8

and take note how \[\Large \frac{49}{9} = \left(\frac{7}{3} \right )^2\]

Answer 9

im still confused on what you just did

Answer 10

I rewrote 49 as 7^2 and 9 as 3^2

So \[\Large \frac{49}{9} = \left(\frac{7}{3} \right )^2\]

Answer 11

5.44=5.44

Answer 12

yes both are roughly equal to 5.44

Answer 13

If so, then which answer would this relate to?

Answer 14

Compare

\[\Large (x-h)^2+(y-k)^2=r^2\]

with

\[\Large (x-(-1))^2+\left(y -\frac{5}{4} \right )^2=\left(\frac{7}{3} \right )^2\]

Answer 15

alright

Answer 16

what is h?

k?

r?

Answer 17

r

Answer 18

@jim_thompson5910

Answer 19

what do you mean

Answer 20

h is 1, k is -5/4, r is 49/9

Answer 21

close

Answer 22

it's 7/3. right?

Answer 23

that's the radius

Answer 24

Its center is at (-1, 5/4), and the radius is 7/3 .

Answer 25

yes

Answer 26

Ok, thank you, now i understand what you were saying above

Answer 27

ok great