Question

HELP!!

y=2^(x+4) +1
Write the equation of the horizontal asymptote in the graph of the function.

HOW do i do this?!

Answer 1

horizontal asymptote is the value of y that will make the function go to infinity...does that give you any ideas?

Answer 2

in all honesty...no im confused..

Answer 3

change it to log form first

Answer 4

log form is like lb * x = y right?

Answer 5

logb * x = y*

Answer 6

\[\log_b x = y\]
that's log form

Answer 7

So...im sorry to be annoying but can you explain step by step by step how to change it?

Answer 8

nahh you're not annoying..but i'll try and see what sir elias has to say first

Answer 9

Notice that
\[
2^{x+4} +1>1\\
\lim_{x->-\infty } 2^{x+4} +1 =1
\]
What can you conclude?

Answer 10

as x gets closer negative inifinity its gets closer to 1?

Answer 11

Look at the attached graph.

Answer 12

So y=1 is the horizontal asymptote.

Answer 13

Did you understand it?

Answer 14

Sort of...so the answer is y =1?

Answer 15

yes.

Answer 16

Thank you!

Answer 17

yw