HELP!!

y=2^(x+4) +1
Write the equation of the horizontal asymptote in the graph of the function.

HOW do i do this?!

Question

HELP!! 

y=2^(x+4) +1 
Write the equation of the horizontal asymptote in the graph of the function.

HOW do i do this?!

lgbasallote · Answer

horizontal asymptote is the value of y that will make the function go to infinity...does that give you any ideas?

anonymous · Answer

in all honesty...no im confused..

lgbasallote · Answer

change it to log form first

anonymous · Answer

log form is like lb * x = y right?

anonymous · Answer

logb * x = y*

lgbasallote · Answer

$$\log_b x = y$$
that's log form

anonymous · Answer

So...im sorry to be annoying but can you explain step by step by step how to change it?

lgbasallote · Answer

nahh you're not annoying..but i'll try and see what sir elias has to say first

anonymous · Answer

Notice that
$$
2^{x+4} +1>1\
\lim_{x->-\infty } 2^{x+4} +1 =1
$$
What can you conclude?

anonymous · Answer

as x gets closer negative inifinity its gets closer to 1?

anonymous · Answer

Look at the attached graph.

anonymous · Answer

So y=1 is the horizontal asymptote.

anonymous · Answer

Did you understand it?

anonymous · Answer

Sort of...so the answer is y =1?

anonymous · Answer

yes.

anonymous · Answer

Thank you!

anonymous · Answer

yw