on interval 0x2pi sec(x)=-1

Question

on interval 0>x>2pi  sec(x)=-1

anonymous · Answer

$$secx = -1 => \frac{1}{cosx} = -1 $$

anonymous · Answer

Are you able to do it now? :)

anonymous · Answer

honestly, im completely clueless all together. haha

anonymous · Answer

well do you know that $$secx = \frac{1}{cosx}$$?

anonymous · Answer

yes

anonymous · Answer

then where are you haveing problems?

anonymous · Answer

what about the PI

anonymous · Answer

I'm just not too sure what exactly the question wants me to do honestly

anonymous · Answer

well looks like the question wants you to solve for $x$
why not try and look in your texbook?

anonymous · Answer

We dont have one yet, since this is summer work

anonymous · Answer

well i know pi is =3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679
but it is 3.14 for shot

anonymous · Answer

that doesnt solve much :P

anonymous · Answer

ya i know just trying to help

anonymous · Answer

0>x>2pi sec(x)=-1
this is hard what grad is this

anonymous · Answer

AP calculus

anonymous · Answer

no no; not hard at all :)
$$secx = -1 => \frac{1}{cosx}   = -1 => 1 = -cosx => -cosx = 1 => cosx = -1 => x = \pi  $$
this is only trig not calculus yet :)

anonymous · Answer

ah must be review problems then. Is that the full answer?

anonymous · Answer

lol the answer got cut off. why not you try and solve it ? :)

anonymous · Answer

not funy

anonymous · Answer

I have no idea what im doing and this is the last problem i have thats due tomorrow lol

anonymous · Answer

:(

anonymous · Answer

need this answer :\