12^x=46^x+3
What about it?
It's only numerically solvable for x, if that's the problem, and even in that case the two solutions are imaginary...
I need to find x
Are you sure you didn't copy it wrong? It's not algebraically solvable...
im sorry it is just 4 not 46
\[12^x = 46^{x+3}\] maybe it's writtent hat way
\[12^x = 4^{x+3}?\]
Thanks, @mathg8 , that really helps...
i am willing to be that \(x+3\) is the exponent
how do you make it like that ^ this means the same thing you wrote doesn't it
Use latex
\[12^x=4^{x+3}\] like that one right?
i'd like it to be x+3 to be the exponent because im a sissy :D
I see ...typo
latex? and its a 4 not 46 yes satelite73 like that
haha okay you really have to be clearer. Maybe with parenthesis.
if you want to see the code, right click on the expression and select "show math as" then "latex"
latex is text-formatting-code-speak for fancy mathy stuff on the internet.
oooo thanks for the tip im sorry didn't mean to confuse any one... i am stressing out my homework is due by midnight and i do not understand ANY of it
ok here is what you do write \[12^x=3^x\times 4^x\] and \[4^{x+3}=4^3\times 4^x\]
or, not using latex, use parentheses: 12^x= 4^(x+3)
cancel a \(4^x\) from both sides, since it is never zero and solve \[3^x=4^3\] i.e. \(3^x=64\)
you good from there?
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