Question

Circle P has a radius of 8 units with center P at (2, -1). Which equation defines circle P?

Answer 1

equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\]
where (h,k) is the center and r is the raidus

does that help

Answer 2

(x + 2)2 + (y – 1)2 = 64

(x – 2)2 + (y + 1)2 = 64

(x – 2)2 + (y + 1)2 = 8

(x + 2)2 + (y – 1)2 = 8

Answer 3

so does your flaunting of the choices mean you didnt get what i said?

Answer 4

Yeah. Haha because none of them matched the - + - pattern

Answer 5

- - means +

Answer 6

^does that make sense?

Answer 7

Yes I know that.

Answer 8

so what's your problem then?

Answer 9

maybe if i show you a demo...

Answer 10

I have to choose which of those defines P.

Answer 11

the center of a circle is (3, -4) and radius is 5

he equation would be \[(x- 3)^2 + (y - -4)^2 = 5^2\]
\[\implies (x-3)^2 + (y+4)^2 = 25\]
got the idea now?

Answer 12

OH I think so, thanks :)

Answer 13

welcome ^_^

Answer 14

The solution is: (x-2)^2+(y+1)^2=64