Evaluate.
\[0.01^{-3/2}\]
\[{1 \over 0.01^{3 \over 2}} \]
Hint: Now you can put that in radical form and simplify!
(Put the denominator in radical form). Remember:\[\large a^{b \over c} \implies \sqrt[c]{a^b}\]
And you'd also be able to simplify the denominator. Try it!
\[\sqrt[3]{0.01^2}\]
Or you could also think of this one:\[\large a^{3 \over 2} \implies a^{1 \over 2} \times a^{1 \over 2} \times a^{1 \over 2} = \sqrt{a} \times \sqrt{a} \times \sqrt{a} \]
\[0.01^{−3/2}=(0.1^{2})^{−3/2}=0.1^{(2\times-3/2)}\]
\[\large 0.01^{3 \over 2} \cdots \cdots \sqrt{0.01} \times \sqrt{0.01} \times \sqrt{0.01}\implies 0.1\times0.1\times0.1 \]
Those are enough of my hints :P
0.001??
Yeah!\[\Huge\ddot \smile \]
@ParthKohli my text gives the answer 1000.
No, not complete yet. Remember how we started with\[\large{1 \over 0.1^{3 \over 2}} \]?
According to our calculation, \(\large 0.1^{3 \over 2} = 0.001\). We now have to find:\[\large {1 \over 0.001} \]
And that, sir, gives us 1000 :)
mm I am lost.
Okay. Do you agree with this one?\[0.01\large^{-3 \over 2} \implies {1 \over 0.01^{3 \over 2}}\]?
yes
Now, do you agree with this?\[\large {1 \over 0.01^{3 \over 2} }\implies {1 \over 0.01^{1 \over 2} \times {0.01^{1 \over 2} \times 0.01^{1 \over 2}}} \]
that makes sense yes.
Now this one?\[1 \over \sqrt{0.01} \times \sqrt{0.01} \times \sqrt{0.01} \]
yes.
Now what is \(\sqrt{0.01}\)?
.1
Yes. That's right. That makes our work simplified to\[1\over 0.1 \times 0.1 \times 0.1 \]Now what is \(0.1\times0.1\times0.1\)?
.001
That's correct again! Now find what\[1 \over 0.001\]is.
I get it.
Great job!
thank you for your time.
You're welcome :)
if you re-write 0.01 as 1/100 the problem is \[ (\frac{1}{100})^{-\frac{3}{2}} \] flip the fraction to get rid of the minus sign on the exponent you get \[ 100^{\frac{3}{2}} \] or \[ (100^{\frac{1}{2}})^3 \] now take the square root of 100 to get 10. 10^3 = 1000 (which is preferred to \(\frac{1}{0.001} \) )
@phi I just spent the last 5 mins doing the same thing lol.
as long as you get to the answer.
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