Question

Algebraic fractions help!

(picture)

So my answer is partially correct, my work is below. Can someone tell me where I may have strayed from getting the correct answer? Thanks!

I first factored everything that could be giving me..
fraction 1: numerator: a^4
denominator: 2a^2(1-2a^2)

fraction 2: numerator: (2a+1)(4a^2-2a+1)
denominator: 2a(2a+1)

I could cancel out the (2a+1) & I did giving me..
(a^4)*(4a^2-2a+1) for the numerator and (2a)(1-2a^2)(2a) for the denominator.

After multiplying the two 2a's together I got...
(a^4)(4a^2-2a+1) for the numerator and (4a^2)(1-2a^2)

Answer 1

(continued..)
for the denominator.

I then did the (a^4) & (2a^2) and made it into (a^2) in the numerator and (4) in the denominator.

After that I multiplied everything together & got my answer.

I hope that makes sense & Thanks for helping!

Answer 2

Where's the picture?

Answer 3

\[\frac{a^4}{2a^2(1-2a^2)} \times \frac{(2a+1)(4a^2-2a+1)}{2a(2a+1)}\]