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What is the solution to the equation 3^(–2x) ≈ 4 ?
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options: x = –0.631 x = –0.396 x = 0.396 x = 0.631
take the log of both \[ln(3^{-2x}=ln(4)\]
you can now pull out the -2x from the top \[-2xln(3)=ln(4)\]
divide by -2ln(3
okay , then what do i do ?
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\[x=\frac{ln(4)}{-2ln(3)}\]
okay , im not really sure what the heck your doing nd idk how to move on .
\[ln(a^b)=bln(a)\]
omgggg ! what are you doinggg ?
i'm using the property \[ln(a^b)=bln(a)\]
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okayy , whats the answerrrr ? :P
nvm , got it !
alright. Sorry about not responding. I was busy with something lse
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