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Mathematics 22 Online
OpenStudy (anonymous):

Fractions within fractions again, help!! (look at the picture) Where do I even start??

OpenStudy (anonymous):

OpenStudy (jkristia):

The easiest is to create a common denuminator in the 'main' numerator', and a common denominator in the 'main' denominator. Then you can you can multiply the 'top' fraction by the inverse of the 'bottom' fraction

OpenStudy (anonymous):

Do you mind showing me what you mean..? Because I am a little confused. & Thank you for helping me :)

OpenStudy (anonymous):

@jkristia do you mind showing me..?

OpenStudy (saifoo.khan):

This one is similar as well. Try it out @theequestrian . No matter if it's wrong. But YOU should try this one!

OpenStudy (anonymous):

Well I tried it & ended up with \[\frac{ x^2+y^2+xy+y}{y}\]

OpenStudy (anonymous):

I looked at it as.. \[\frac{1}{x} + \frac{1}{y} \div \frac{1}{x}-\frac{1}{y}\]

OpenStudy (saifoo.khan):

Incorrect.

OpenStudy (saifoo.khan):

\[(x + \frac xy) \div (y - \frac 1y)\]

OpenStudy (anonymous):

Crud. But wouldn't you now multiply everything by 1/y?

OpenStudy (anonymous):

Wait, no I meant y/1 not the other way around

OpenStudy (saifoo.khan):

Yes, you are correct. But not everything. ONLY the left's x and the y in right parenthesis.

OpenStudy (anonymous):

But wouldn't you have to apply it to everything to keep it even?

OpenStudy (anonymous):

Right?

OpenStudy (saifoo.khan):

Sorry, i was afk Are you here? @theequestrian

OpenStudy (anonymous):

Your fine & yes !

OpenStudy (saifoo.khan):

Yes, you have to do it: |dw:1344273479208:dw|

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