Question

Can someone please help me!!!



Use the definition of the Laplace Transform to find the transform of the function shown in the link

https://instruct.math.lsa.umich.edu/webwork2_course_files/ma216-u12/tmp/gif/rilayian-103-sethomework6prob13image1.png

Answer 1

@Spacelimbus

Answer 2

@TuringTest

Answer 3

@ranyai12 you there ?

Answer 4

yes i am

Answer 5

ok

Answer 6

you have given piecewise function .first the definition of Laplace is
\[[\Large F(s)=\int\limits\limits_{0}^{\infty}e^{-st}f(t)dt\]\]

Answer 7

sorry openstudy logged me out!

Answer 8

what values from the graph would we incorporate?

Answer 9

@sami-21 are you still there?

Answer 10

yes i am here . openstudy crashed me :( i was typing everything went off :(
let me try again.

Answer 11

OpenStudy is a bit of a pain today, I was opening this question about 20 minutes ago, and by now I am here hehe.

Answer 12

lol yea i understand it kept on logging me out!

Answer 13

it is piece wise function can be written as

Answer 14

do you get the integration to be (-3e^(-st))/s

Answer 15

yes apply the limits

Answer 16

and the limits are the s right

Answer 17

nopes!! they are for t :P

Answer 18

oh lol

Answer 19

ok so the answer would be (3e^(-5s)(3e^s-1))/s

Answer 20

you did a mistake .
first take 3 common also the second one should be e^(-2s)

Answer 21

what do you mean first take 3 common

Answer 22

so the answer is 3(e^5s/s-e^2s/s)

Answer 23

\[\Large \frac{-3}{s}|e^{-st}|_{2}^{5}=\frac{-3}{s}[e^{-5s}-e^{-2s}]\]

Answer 24

@ranyai12 yes it is just you missed minus sign with the s in the exponent.

Answer 25

oh ok thank you

Answer 26

you 're welcome :)

Answer 27

it ended up being wrong

Answer 28

wait nevermind i got it!

Answer 29

it was right! i plugged it in wrong

Answer 30

(-: !

Answer 31

you must have missed minus sign with 3 :P

Answer 32

I did! lol