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Find the polar coordinates for the point (x,y) = (-sqrt(3),1) use Radians.
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what is r?
-sqrt(3)?
Hey I remember you!
:)
r = sqrt(x^2 + y^2)
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what is theta?
I thought that r was x and theta was y?
Nah.
what's the point of that?
No idea I'm super konfused haha....
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idk from this example 4,5pi/4 it's saying that x,y is 4cos(5pi/4),4sin(5pi/4)
The idea is that if we draw a line from the origin to the point x,y we can also think of it as having some length r and some angle with the x-axis, theta.
You understand that?
mhm.
sounds like arc length, or somethinh we used in physics....
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|dw:1344299153108:dw|
so I guess in a sense we are doing it all backwards...
|dw:1344299162572:dw|
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