Square root help (well, cube root) Alg. II

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Question

Square root help (well, cube root) Alg. II

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anonymous · Answer

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anonymous · Answer

think of a number that when you multiply by itself 4 times would equal to 32

helder_edwin · Answer

$$ \large \frac{1}{2}\sqrt[4]{32}=\frac{1}{2}\sqrt[4]{2^5} $$

anonymous · Answer

that's not helpful.. lol but good work

helder_edwin · Answer

$$ \large =\frac{1}{2}\sqrt[4]{2^4}\sqrt[4]{2}= $$

anonymous · Answer

$$\sqrt[4]{2^4 * 2}$$

anonymous · Answer

I hope that makes sense and that you can continue solving from

phi · Answer

I would factor 32 into its prime factors
2*2*2*2*2  (keep dividing by 2)
now look for 4 of the same number.  take those out of the 4th root
we get
$$2\sqrt[4]{2}$$

anonymous · Answer

use this website really helps http://mathway.com/problem.aspx?p=algebra

phi · Answer

then multiply by 1/2  to get the final answer

anonymous · Answer

Well do I just multiply the number in front of the radical or the radical too?

anonymous · Answer

& Thanks so much y'all (: