Question

Square root help (well, cube root) Alg. II

(picture)

Answer 1

think of a number that when you multiply by itself 4 times would equal to 32

Answer 2

\[ \large \frac{1}{2}\sqrt[4]{32}=\frac{1}{2}\sqrt[4]{2^5} \]

Answer 3

that's not helpful.. lol but good work

Answer 4

\[ \large =\frac{1}{2}\sqrt[4]{2^4}\sqrt[4]{2}= \]

Answer 5

\[\sqrt[4]{2^4 * 2}\]

Answer 6

I hope that makes sense and that you can continue solving from

Answer 7

I would factor 32 into its prime factors
2*2*2*2*2 (keep dividing by 2)
now look for 4 of the same number. take those out of the 4th root
we get
\[2\sqrt[4]{2}\]

Answer 8

use this website really helps
http://mathway.com/problem.aspx?p=algebra

Answer 9

then multiply by 1/2 to get the final answer

Answer 10

Well do I just multiply the number in front of the radical or the radical too?

Answer 11

& Thanks so much y'all (: