Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\int\limits_{0}^{2}\sqrt{1+\cosh^2(x)}dx\]
OpenStudy (lgbasallote):
this sounds fun
OpenStudy (anonymous):
not so much
OpenStudy (lgbasallote):
wolfram gives a scary answer
OpenStudy (anonymous):
yeah i need steps
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (lgbasallote):
i have no clue sorry...if wolfram gives a frightening answer idk if i am able to solve it o.O
OpenStudy (anonymous):
@Spacelimbus
OpenStudy (lgbasallote):
although....if you wrote the question wrong it could be possible to solve..
OpenStudy (anonymous):
nope ;that is right
OpenStudy (anonymous):
I remember the elliptical integral function actually, but I doubt that this will help us anywhere here, I will have to take a look if some substitutions will work.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Lets try it :D
OpenStudy (anonymous):
Actually, you can't integrate it.
OpenStudy (anonymous):
a series representation might work.
OpenStudy (anonymous):
why?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Its an elliptic integral, just type it into wolfram. It doesn't have an antiderivative.
OpenStudy (anonymous):
what about \[d/dx e^x-e ^{-x}\div 2\]
OpenStudy (anonymous):
what you have makes no sense. You're integrating. Also:
\[\cosh(x)=\frac{e^x+e^{-x}}{2}\]
Not minus, thats sinh(x).