Question

how do you enter the equation of the circle in standard form with center and radius given.

Center (-8, -3), radius = 2

Answer 1

radius= 2 sqrt 3

Answer 2

\[(x-h)^2+(y-k)^2=r^2\] with \(h=-8, k=-3, r=2\)

Answer 3

ok but how do you do it with the sqrt?

Answer 4

your radius is \(2\sqrt{3}\) right ?

Answer 5

yes

Answer 6

but the equation needs \(r^2\) so take \(2\sqrt{3}\) and square it (multiply it by itself)
clear or no?

Answer 7

so that would make it 6?

Answer 8

no you have to square 2 as well

Answer 9

so 12?

Answer 10

yes

Answer 11

ok thank you

Answer 12

yw