How do I rewrite x^2 + 14x +49 in (a+b)^2 or (a-b)^2?
(x+a)^2 = x^2 + a^2 + 2ax ex: (x+6)^2 = x^2 + 6^2 + 2*6x = x^2 + 36 + 12x
Isnt it (x+7)^2 +14x?
Very near :) Its (x+7)^2 (x+7)^2 = x^2 + 2*7x +7^2 = x^2 + 14x +49
okay so for x^2-16x+64 it is (x+8)^2 -2*8x?
If u see a negative sign, (x - a)^2 = x^2 + a^2 - 2ax ex: (x- 6)^2 = x^2 + 6^2 - 2*6x = x^2 + 36 - 12x x^2-16x+64 = (x - 8)^2
That confused me... okay so you ignored the -16x in the last line
First, you have to break it up into (x....)(x....) and then you must figure out the factors of 49 that make 14 when added. So you can make it into (x+7)(x+7). There is two of the same factors so you can make it into (x+7)^2
lemme show it again: If u see a negative sign, (x - a)^2 = x^2 - 2ax + a^2 ex: (x- 6)^2 = x^2 - 2*6x+ 6^2 = x^2 - 12x + 36 (x - 8)^2 = x^2-2*8x+8^2 = x^2-16x+64
Oh! okay thank you ! :)
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