Question

ln(x)+ln(x+2)=ln(8)
i started with ln(x(x+2)=ln(8)
so I have ln(x^2+2x)=ln(8)
what next?

Answer 1

subtract ln 8 from both sides

ln (x^2 + 2x) - ln 8 = 0

Answer 2

do you see the next step now?

Answer 3

I tryed that then it would be ln (x^2+2x)/8 then how do i solve from there

Answer 4

ln (x^2 +2x)/8 = 0

that = 0 is very important

Answer 5

now you turn it into exponential form...ln has a base e right? so in exponential form it becomes \[e^0 = \frac{x^2+2x}{8}\]
agree?

Answer 6

ok i got that so e^0 equals 1 so then i can just solve for x?

Answer 7

yup

Answer 8

and it cannot be negative correct?

Answer 9

yep..because you have an ln x

Answer 10

thanks

Answer 11

x+2 cannot be negative or equal to 0 as well so x has to be greater than 2