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Mathematics 15 Online
OpenStudy (anonymous):

Alg...Did I do this correctly? Question: What is the difference of x over x-3 and 5x-1 over x^2-6x+9 My answer: x^2-5x-1 over (x-3)^2

OpenStudy (anonymous):

\[{x\over x-3}~~-{5x-1\over x^{2}-6x+9} ~~~~~~~~~~?\]

OpenStudy (anonymous):

Yes^

OpenStudy (anonymous):

okay well to simplify we must have common denominators :) \[({x-3\over x-3}~~\times{x\over x-3}~~)-{5x-1\over x^{2}-6x+9}\]\[{x^2-3x\over x^2-6x+9}~~~~~-{5x-1\over x^{2}-6x+9}\]now simplify the numerators\[{x^2-8x-1\over x^{2}-6x+9}\]

OpenStudy (anonymous):

So the common denominator is x^2-6x+9?

OpenStudy (anonymous):

yup :)

OpenStudy (anonymous):

Would the final answer be x^2-2x-1 over (x-3)^2

OpenStudy (anonymous):

i think your add wrong..the middle term on the numerator should be -8x not -2x ...check again :)

OpenStudy (anonymous):

you're adding*

OpenStudy (anonymous):

Oh, I was thinking the 5x was positive, now I understand, Thanks! ^_^

OpenStudy (anonymous):

anytime! :D

OpenStudy (anonymous):

you could factor the fraction but it wouldnt get you anywhere so yup thats your final answer! :)

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