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1. For i = −1, if 3i(2 + 5i) = x + 6i, then x = ? A. –15 B. 5 C. 5i D. 15i E. 27i please explain. :D
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What do you get when you distribute 3i(2 + 5i)
5i+15i?
6i* i ment
6i is correct, but it should be 15i^2 since i*i = i^2
so it's really 6i + 15i^2
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but what is i^2 really?
1?
close
\[\Large i = \sqrt{-1}\] square both sides
i do not know.
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squaring a square root effectively undoes it
and they cancel
\[\Large i = \sqrt{-1}\] \[\Large i^2 = \left(\sqrt{-1}\right)^2\] \[\Large i^2 = -1\]
then?
so 15i^2 is really 15(-1) = -15
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ohh
3i(2 + 5i) 6i + 15i^2 6i + 15(-1) 6i + (-15) -15 + 6i
3i(2 + 5i) = x + 6i -15 + 6i = x + 6i I'm sure you can see what x is
Thank you.
yw
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