@jim_thompson5910

So here is another one if you don't mind helping..

But this time I don't know whether to substitute what I get for the first equation (x+y=6 turns into y=6-x) for y or y^2. Does that make sense..?

Question

@jim_thompson5910 

So here is another one if you don't mind helping..

But this time I don't know whether to substitute what I get for the first equation (x+y=6 turns into y=6-x) for y or y^2. Does that make sense..?

anonymous · Answer

attachment

jim_thompson5910 · Answer

Solve for either x or y. It doesn't matter. I'm going to choose y and it's easiest to solve for y in the second equation.


x+y = 6

y = -x+6

Now replace 'y' in the first equation with -x+6 to get

x^2 + y^2 = 36

x^2 + (-x+6)^2 = 36

Now solve for x

jim_thompson5910 · Answer

You replace y and NOT y^2 because y = -x+6. If you had y^2 = -x+6, then you would replace all of y^2

anonymous · Answer

That makes sense, but I was a wee bit confused. & I got x=0 & x=6

jim_thompson5910 · Answer

good, that's part of it

jim_thompson5910 · Answer

now use those x values to find the corresponding y values

anonymous · Answer

Then when I subsituted it back in I got y=6 & y=0. So my points are (0,6) & (6,0) yes?

jim_thompson5910 · Answer

you nailed it again

anonymous · Answer

With your help again! Thanks a million and two :)

jim_thompson5910 · Answer

you're welcome