(3(n+1)!)/(5n!)
hint: \[(n+1)! = (n+1) \times n!\] does that help?
btw...you wouldnt happen to be in an online class would you? i noticed the random jumps in topics...
I think I need more help, my math class last year did not go over factorials, which is kind of dumb. And answering your other question, no I am not. My teacher gave us a packet of random math questions to do over the summer.
well okay... \[\huge \frac{3(n+1)!}{5n!} \implies \frac{3(n+1) \times n!}{5n!}\] do you see how i got that?
how did you get the n! ?
look what i wrote earlier \[\huge (n+1)! = (n+1) \times n!\] would you like to know why this is so?
yes please.
this just goes by the basic principle of factorials \[\LARGE a! = a \times (a-1) \times (a-2) \times (a-3) \times \cdots \times 1\] do you get the principle of the factorials?
Oh yes, yes. I understand the problem now. Thanks.
wonderful
so you know how to proceed now?
yes, i have to cancel out the n! and simplify what's left, right?
yup
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