Question

y=2^x+1
find the y-intercept as an ordered pair and find the range

Answer 1

\[y = 2^{x+1}\]
to find the y-intercept let x = 0 then solve for y

Answer 2

wait...my mistake

Answer 3

\[\huge y = 2^x + 1\]
to find y-intercept let x = 0 then solve fory

Answer 4

for y*

Answer 5

yes

Answer 6

the small x^ is confusing to me

Answer 7

if you let x = 0 it will become
\[\huge y = 2^0 + 1\]
right?

Answer 8

ok

Answer 9

...ok?

Answer 10

so when you have a 0 ^ how does that effect the 2?

Answer 11

does it leave it as a 2 or make it a 0

Answer 12

it becomes a 1

Answer 13

anything to the power of 0 becomes a 1

Answer 14

so y=2

Answer 15

yeah y=2 when x=0

put those values into order pair form

(x,y)

Answer 16

(0,2)....how do I find the y intercept

Answer 17

that is the y-intercept...

Answer 18

sorry I meant the range

Answer 19

to find the range, you start by solving for x..do you know how to? or do you need more help?

Answer 20

so if I make x=1 then y=3 (1,3)

Answer 21

why would you make x = 1?

Answer 22

what do you mean solving for x?

Answer 23

you make the equation look like x =

need help?

Answer 24

I don't know how to do that when it is a "^"