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Mathematics 10 Online
OpenStudy (maheshmeghwal9):

What is homogenous function? Please explain me in easy way:)

OpenStudy (lgbasallote):

is this a differential equation question?

OpenStudy (maheshmeghwal9):

no i m only a beginner of calculus i want only some explanation:)

OpenStudy (lgbasallote):

sorry i got aw snapped..let me rewrite..

OpenStudy (maheshmeghwal9):

np:)

OpenStudy (lgbasallote):

to determine if a function is homogeneous or not, substitute x and y with \(\lambda x\) and \(\lambda y\) respectively. after that, simplify the function. if the function becomes in the form \(\lambda ^n f(x,y)\) then it is a homogeneoous function. for example f(x,y) = x^3 + y^2 + 1 if i substitute i get \[(\lambda x)^3 + (\lambda y)^3 + 1\] \[\implies \lambda ^3 x^3 + \lambda ^2 y^2 +1 \] \[\implies \lambda^2 (\lambda x^3 + y^2) +1\] this does not look like \[\lambda^n f(x,y)\] this is how a homogeneous function should look like f(x,y) = x^2 + y^2 substitute.. \[(\lambda x)^2 + (\lambda y)^2\] \[\implies \lambda ^2 x^2 + \lambda^2 y^2\] \[\implies \lambda ^2 (x^2 + y^2)\] this looks like \(\lambda ^2 f(x,y)\) right? therefore it is homogeneous.. does that help?

OpenStudy (lgbasallote):

...that nostalgic feeling of writing tutorials =))

OpenStudy (maheshmeghwal9):

gt it thanx:)

OpenStudy (lgbasallote):

welcome ^_^ and glad you got it...i was worried i wasnt articulate enough

OpenStudy (maheshmeghwal9):

^_^

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