Mathematics
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OpenStudy (anonymous):
Please find attached.
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OpenStudy (anonymous):
OpenStudy (lgbasallote):
hahaha
OpenStudy (anonymous):
I rearrange it so ahahah/ha=joke.
OpenStudy (saifoo.khan):
now suppose the values for A and H.
OpenStudy (saifoo.khan):
No it wont work. sorry.
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OpenStudy (saifoo.khan):
This might work:
122112/21
OpenStudy (saifoo.khan):
Suppose the value for A = 1, H = 2
And then re-write them.
you'll get 5814.86
OpenStudy (saifoo.khan):
After rounding off, 5815.
JOKE = 5815
OpenStudy (anonymous):
sorry but that is wrong
OpenStudy (saifoo.khan):
Oh! right. It can't be that. This is because the values of J and E are same. Whereas they shouldn't be.
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OpenStudy (saifoo.khan):
@sami-21 , dimagh larao bhai.
OpenStudy (lgbasallote):
i think @saifoo.khan was solving for TROLL
OpenStudy (saifoo.khan):
No, your thinking is wrong @lgbasallote . :D
OpenStudy (saifoo.khan):
I am actually trying to solve this question.
OpenStudy (anonymous):
usually decoding key is provided for such questions.
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OpenStudy (anonymous):
\[\frac{AHHAAH}{HA}=\frac{10000AH+100HA+AH}{HA}=100+10001\frac{AH}{HA}\]
OpenStudy (anonymous):
and \[10001=73*137\]\(73\) and \(137\) are \(2\) primes so \(HA=73\) it gives
\[\large \frac{377337}{73}=5169\]
OpenStudy (anonymous):
dude!
OpenStudy (saifoo.khan):
Awesome @mukushla
OpenStudy (anonymous):
tnx saifoo...:)
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OpenStudy (anonymous):
@mukushla HOW?????
OpenStudy (anonymous):
which part?
OpenStudy (anonymous):
1000AH+100HA+AH how did that come about?
OpenStudy (anonymous):
for example ---------> 672618=10000*67+100*26+18
OpenStudy (anonymous):
aye