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Mathematics 19 Online
OpenStudy (anonymous):

Please find attached.

OpenStudy (anonymous):

OpenStudy (lgbasallote):

hahaha

OpenStudy (anonymous):

I rearrange it so ahahah/ha=joke.

OpenStudy (saifoo.khan):

now suppose the values for A and H.

OpenStudy (saifoo.khan):

No it wont work. sorry.

OpenStudy (saifoo.khan):

This might work: 122112/21

OpenStudy (saifoo.khan):

Suppose the value for A = 1, H = 2 And then re-write them. you'll get 5814.86

OpenStudy (saifoo.khan):

After rounding off, 5815. JOKE = 5815

OpenStudy (anonymous):

sorry but that is wrong

OpenStudy (saifoo.khan):

Oh! right. It can't be that. This is because the values of J and E are same. Whereas they shouldn't be.

OpenStudy (saifoo.khan):

@sami-21 , dimagh larao bhai.

OpenStudy (lgbasallote):

i think @saifoo.khan was solving for TROLL

OpenStudy (saifoo.khan):

No, your thinking is wrong @lgbasallote . :D

OpenStudy (saifoo.khan):

I am actually trying to solve this question.

OpenStudy (anonymous):

usually decoding key is provided for such questions.

OpenStudy (anonymous):

\[\frac{AHHAAH}{HA}=\frac{10000AH+100HA+AH}{HA}=100+10001\frac{AH}{HA}\]

OpenStudy (anonymous):

and \[10001=73*137\]\(73\) and \(137\) are \(2\) primes so \(HA=73\) it gives \[\large \frac{377337}{73}=5169\]

OpenStudy (anonymous):

dude!

OpenStudy (saifoo.khan):

Awesome @mukushla

OpenStudy (anonymous):

tnx saifoo...:)

OpenStudy (anonymous):

@mukushla HOW?????

OpenStudy (anonymous):

which part?

OpenStudy (anonymous):

1000AH+100HA+AH how did that come about?

OpenStudy (anonymous):

for example ---------> 672618=10000*67+100*26+18

OpenStudy (anonymous):

aye

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