Question

|6 - (3/x)| < 1

Answer 1

\[-1<6-\frac{3}{x}<1\] is a start

Answer 2

then you need so solve two inequalities
\[-1<\frac{6x-3}{x}\] and \[\frac{6x-3}{x}<1\]
or
\[0<\frac{6x-3}{x}+1\]and
\[\frac{6x-3}{x}-1<0\]

Answer 3

thank you! simple question i forgot how to do : )

Answer 4

yw
it is still a pain because you have to solve
\[0<\frac{7x-3}{x}\]and also
\[\frac{5x-3}{x}<0\]

Answer 5

so i get (3/7) < x < (3/5). does that seem right?