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Mathematics 21 Online
OpenStudy (anonymous):

Help!! Write the nth term of the following sequence in terms of the first term of the sequence. a, a + 4, a + 8, . . . @sauravshakya I tried to use the formula you gave me (nth=a+(n-1)d) because I thought it was arithmetic. It would be arithmetic, right? But if someone else can help, that would be great too!

OpenStudy (anonymous):

the formula is a+(n-1)d a=first term of the sequence d=common difference

OpenStudy (anonymous):

it is an arithmetic sequence

OpenStudy (anonymous):

That's what I thought. & I got a+4n-4. Did I do it correct?

OpenStudy (anonymous):

right............good

OpenStudy (anonymous):

But there is just a slight problem.. It says that it is incorrect.

mathslover (mathslover):

what is the correct answer then @theequestrian ?

OpenStudy (anonymous):

I don't know, I'm still trying to figure that out..

mathslover (mathslover):

k wait

mathslover (mathslover):

well the formula applied is right

mathslover (mathslover):

the answer that you got is perfect that is it is right no mistake there

OpenStudy (anonymous):

Hmm. Hold on

mathslover (mathslover):

Why not? holded .. :D

OpenStudy (anonymous):

So this is what my answer is supposed to look like & I have to start in the first square

mathslover (mathslover):

so u can insert a + 4n - 4 there

mathslover (mathslover):

is it necessary to fill all squares?

OpenStudy (anonymous):

& this is what it looks like when I minster my answer in from above

OpenStudy (anonymous):

Well I can fit it & I don't have to use every square, but I do have to start with the first one, like in the last picture do you see how I have a blank space at the first one? I can't do that..

mathslover (mathslover):

you mean u r unable to put a in the first square

OpenStudy (anonymous):

Yes. Like it allows me to, but it won't fit, let me show you

OpenStudy (anonymous):

this is how it would look if I started with a in the first square, but I can't have spaces within my equation.

OpenStudy (anonymous):

& thank you for helping, this one is yuckkyy

OpenStudy (anonymous):

Does that make sense?

mathslover (mathslover):

well shift the first bracket ( left block

OpenStudy (anonymous):

I can't.. They have that one already in place & I can't move it

mathslover (mathslover):

.. hmn sorry to say : but i can not help further .. m really stuck in this now .. sorry

OpenStudy (anonymous):

It's okay, it'll stump the best of us ! I'll ask my teacher. Thanks for trying though, I really appreciate it :)

mathslover (mathslover):

thanks and best of luck @theequestrian have to go now sorry again

OpenStudy (anonymous):

Don't even sweat it, & thanks :)

mathslover (mathslover):

.:)

OpenStudy (anonymous):

Your answer is correct. The only issue I can think of is that it asks you to put it in terms of the first term of the sequence. Does it consider a to be an adaquate name for the first term of the sequence, or is there some other preference for how it should be indicated, like \(a_1\) or something? The good news is that it really just comes down to how you have to input this to get the system to accept your answer.

OpenStudy (anonymous):

Can I just switch the terms around..?

OpenStudy (anonymous):

That shouldn't matter. The truth is, I don't know how this system is designed, so I don't know how it will read your answer or what the requirements or for what it will accept. All I know is how it SHOULD read your answer, and what it SHOULD accept.

OpenStudy (anonymous):

Oh well. At least I have the right answer :) Haha

OpenStudy (anonymous):

Gracias :)

OpenStudy (anonymous):

Just incase it truly bugged someone, I have the answer now. I had to factor out the 4 from the last two terms which gave me a+4(n-1) as my answer. Thanks again for all y'alls help! Much appreciated!!!

OpenStudy (anonymous):

-_- hmph. Well that's dumb.

OpenStudy (anonymous):

I knowwww!!!!!!!! I thought the same thing.

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