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Mathematics 15 Online
OpenStudy (anonymous):

can anyone give a sample equation where you have to compute the domain?

OpenStudy (anonymous):

Like find the domain?

OpenStudy (anonymous):

It does not have to be solved...just need an example of an equation where I would have to compute the domain

OpenStudy (anonymous):

really depends on the topic

OpenStudy (anonymous):

a function with a rational expression

OpenStudy (anonymous):

domain of \(\sqrt{1-x}\) domain of \(\frac{x^2-4}{x-2}\) domain of \(\log(x)\) domain of \( \sqrt{25-x^2}\)

OpenStudy (anonymous):

oh if it is a rational expression, set the denominator equal to zero and solve you may not divide by zero, so exclude your answers

OpenStudy (anonymous):

sometimes you can do it in your head \[\frac{x}{x-4}\] domain is all numbers except 4

OpenStudy (anonymous):

sometimes you have to do more, like factor or use the quadratic formula, like for example in \[\frac{x+5}{x^2-4x+3}\]

OpenStudy (lgbasallote):

how about \[\huge \log_ 2 \left( \frac{\sqrt{3x - 4}}{\sqrt{2x + 5}} \right )\]

OpenStudy (anonymous):

Good job @satellite73 So many good examples. "brohoof"

OpenStudy (anonymous):

and sometimes even if you have a rational expression, the domain in all real numbers like for example in \[\frac{x}{x^2+1}\]

OpenStudy (lgbasallote):

@satellite73 what about if you have \[\frac{x+5}{x^2 + 6x + 5}\] would the domain restriction be -1 and -5? or just -1? hmm?

OpenStudy (anonymous):

what do you think?

OpenStudy (lgbasallote):

well i think it's -1 and -5..

OpenStudy (anonymous):

then you would be correct

OpenStudy (lgbasallote):

nice

OpenStudy (anonymous):

Thanks to all who responded to my question. All the answers were da bomb!

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