can the "average" plus one standard deviation be greater than 100%? for example : the employment rate for students is 97% with a SD of 5. Is this possible? It does not say it is normal distrubution.
how di you get the std div?
the mean is 50% of the data; and 1sd from the mean contains 34% of the data or so
I received it from an organization but I think this is impossible, therefore their data is inaccurate.
what is the type of distribution? normal, poisson, etc
they reported the mean employment rate is 97% with a standard deviation of 5%. I told them that is impossible to have one SD be greater than 100%.
They could not answer that but we assume normal
it looks like they are using proportion instead of mean .... but without knowing their processes its hard to reconsruct it
different schools submit their employment rate (approx 250) they give us the mean and the SD. It should be a normal dist.... correct?
they report 97% is the "average"
should be? no. Do not try to conform the data; let the data conform itself
amistre64: thanks so much for your help! Greatly appreciated.
yw, but i think satellite, or others might be more useful in this since they are more adept than i :)
@satellite73
sorry i an statistically challenged
http://stattrek.com/hypothesis-test/proportion.aspx if your able to parse this, it might be useful
relative standard deviation is usually expressed in percentages .... from the wiki
ok, I believe this is normal dist. all schools reported their employment rates. We are not using a probability in this case.
RSD = sd/mean sd = RSD*mean, in this case; sd = .0485 if they are relaying a relative standard deviation
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