Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

can the "average" plus one standard deviation be greater than 100%? for example : the employment rate for students is 97% with a SD of 5. Is this possible? It does not say it is normal distrubution.

OpenStudy (unklerhaukus):

how di you get the std div?

OpenStudy (amistre64):

the mean is 50% of the data; and 1sd from the mean contains 34% of the data or so

OpenStudy (anonymous):

I received it from an organization but I think this is impossible, therefore their data is inaccurate.

OpenStudy (amistre64):

what is the type of distribution? normal, poisson, etc

OpenStudy (anonymous):

they reported the mean employment rate is 97% with a standard deviation of 5%. I told them that is impossible to have one SD be greater than 100%.

OpenStudy (anonymous):

They could not answer that but we assume normal

OpenStudy (amistre64):

it looks like they are using proportion instead of mean .... but without knowing their processes its hard to reconsruct it

OpenStudy (anonymous):

different schools submit their employment rate (approx 250) they give us the mean and the SD. It should be a normal dist.... correct?

OpenStudy (anonymous):

they report 97% is the "average"

OpenStudy (amistre64):

should be? no. Do not try to conform the data; let the data conform itself

OpenStudy (anonymous):

amistre64: thanks so much for your help! Greatly appreciated.

OpenStudy (amistre64):

yw, but i think satellite, or others might be more useful in this since they are more adept than i :)

OpenStudy (amistre64):

@satellite73

OpenStudy (anonymous):

sorry i an statistically challenged

OpenStudy (amistre64):

http://stattrek.com/hypothesis-test/proportion.aspx if your able to parse this, it might be useful

OpenStudy (amistre64):

relative standard deviation is usually expressed in percentages .... from the wiki

OpenStudy (anonymous):

ok, I believe this is normal dist. all schools reported their employment rates. We are not using a probability in this case.

OpenStudy (amistre64):

RSD = sd/mean sd = RSD*mean, in this case; sd = .0485 if they are relaying a relative standard deviation

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!