Find the steady state solution of y''+2y'+2y=cos(wt). Also find the w so that the amplitude of the steady state solution is maximal.
u mean to Find the steady state solution of the differential equation WITHOUT determining the exact solution and taking \(t\) to infinity ?
note that the characteristic equation is \(m^2+2m+2=0\) which has roots \[m=-1\pm i\] so u have\[y=e^{-t}(A \cos t+B \sin t)+C \sin \omega t+D \cos \omega t\]
so Actually particular solution will be the steady state solution because the rest of general solution goes to zero exponentially as \(t\rightarrow \infty\)
so just detemine the coefficients of particular solution using undetermined coefficients...
anyway after finding \(C\) and \(D\) in terms of \(\omega\) your amplitude will be \[f(\omega)=\sqrt{C^2(\omega)+D^2(\omega)}\] then u can find \(\omega\) for which \(f(\omega)\) or amplitude is maximum
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