Question

The block B of mass m is on the smooth inclined surface of wedge A and mass M on a smooth floor what should be the magnitude of the horizontal force F to be applied on A so that B will not slide on the inclined surface?

Answer 1

\[
F= m g \tan(\theta)
\]
Am I right?

Answer 2

\[ Nsin\theta = ma = m \cdot \frac{F}{m + M} \]
\[ Ncos\theta = mg \]
Divide both the equations:
\[ tan\theta = \frac{F}{g(m + M)} \]
\[ F = (M + m)g \cdot tan\theta \]

Should be correct (though not sure)