Find the gradient of the tangent to the curve when y =x^3-3x^2+x-5 at the point (-1,-10)

Question

anonymous · Answer

Do you know what it means for a line to be tangent to a function at a given point? Like the most important condition.

anonymous · Answer

Noo

anonymous · Answer

A line is tangent to a given point at a function if and only if their slope is identical.

anonymous · Answer

So how do i find the gradient

anonymous · Answer

Has to do with the derivative, decides about the slope of a function at any given point.

anonymous · Answer

I still cant solve it

anonymous · Answer

1) take the derivative 
2) replace $x$ by $-1$ to get the slope a that point

anonymous · Answer

Is taking the derivative a problem for you @Ayeshaafzal ?

anonymous · Answer

Answer is 10 but my answer is coming 4

anonymous · Answer

Mind to show us your work? What is your derivative?

anonymous · Answer

No its just 2 in the morning and my brain is numb

anonymous · Answer

Good, I understand that.

$$ \Large  f'(x) = 3x^2-6x+1$$

Now compute $ f'(-1)$ and you will get your answer