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Physics 17 Online
OpenStudy (anonymous):

How many joules of heat energy would be needed to raise the temperature of 125 grams of water from 22.0° C to 57.0° C? The specific heat capacity of liquid water is 4.18 J/ (°C × g). 1.17 J 14.9 J 1050 J 18300 J

OpenStudy (anonymous):

Heat energy = mass * specific heat capacity * change in temperature

OpenStudy (anonymous):

i'm getting 18287.5 J :S

OpenStudy (anonymous):

so it would be: 125*4.18*35?

OpenStudy (anonymous):

I got the same thing :/

OpenStudy (anonymous):

yeah, exactly

OpenStudy (anonymous):

Well rounded it would be D right?

OpenStudy (anonymous):

yeah.. i'll go with D ;)

OpenStudy (anonymous):

Thank you!(:

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