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OpenStudy (anonymous):
OK GUYS new question :) (easier, i think :P )
f(x) = 2x + 1
f(g(x)) = 1/(2x+1)
What is g(x) ??
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OpenStudy (amistre64):
how do we turn f(x) into f(g(x)) by altering the x part?
OpenStudy (amistre64):
it might be easier to say f(a) instead of f(x) limits the amount of x on x confusion to me
OpenStudy (anonymous):
but the point of using x, is that in the equation the variables are called x :P
OpenStudy (amistre64):
i know, but to separate the x in f and the x in g is useful ....
say f(a) = 2a+1; then g(x) = a
OpenStudy (amistre64):
2a+1 = 1/(2x+1)
solve for a, since a = g(x)
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OpenStudy (amistre64):
or ... to keep your preciuous xs :)
2g(x) + 1 = 1/(2x+1)
and solve for g(x)
OpenStudy (amistre64):
subtract 1 and divide off the 2
OpenStudy (anonymous):
HAWW I DIDN'T THINK OF THAT WAIT.
OpenStudy (anonymous):
so i got (2x + 1)/-x now what :P
OpenStudy (amistre64):
2g(x) + 1 = 1/(2x+1)
2g(x) = 1/(2x+1) - 1
g(x) = 1/2(2x+1) - 1/2
g(x) = 1/2(2x+1) - 1/2 is what i get
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OpenStudy (anonymous):
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