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Mathematics 10 Online
OpenStudy (anonymous):

ODE problem confused!

OpenStudy (anonymous):

OpenStudy (anonymous):

Confused on b(ii)

OpenStudy (anonymous):

I'm not sure what to do.

OpenStudy (anonymous):

I have to find u somehow I reckon, not 100% though.

OpenStudy (anonymous):

Hmm I believe you just have to show that the identity is valid, because the roots are identical.

OpenStudy (anonymous):

pretty similar to the part before it

OpenStudy (anonymous):

But I will try first.

OpenStudy (anonymous):

the other solution will have an additional x infront of it I am not mistaken.

OpenStudy (anonymous):

juts plug it in and see what happens

OpenStudy (experimentx):

http://en.wikipedia.org/wiki/Reduction_of_order

OpenStudy (anonymous):

If it's double roots then yes there's extra x in the solution.

OpenStudy (anonymous):

I'm still not sure what should I do first.

OpenStudy (anonymous):

I don't know what u is.

OpenStudy (experimentx):

assume that \( x(t) = u(t) x_1(t) \) is another solution ... find the value of u(t) ... so that you have complete solution.

OpenStudy (anonymous):

Still lost...

OpenStudy (anonymous):

@experimentX I genuinely don't know where to start.

OpenStudy (experimentx):

i think there is an example in the wikipedia ... in the link i posted above.

OpenStudy (anonymous):

If I understand this problem then they just want you to check what happens if you substitute back their provided result. I believe their are trying to introduce you to the method of Reduction of Order You will get a result in the form of \[ \Large u(x)=d_1x+d_2 \] where \(d_1, d_2\) are constant. The second solution is of the form \[ \Large y_2(x)=u(x)e^{\frac{x}{2}}\] So you can use superposition to get the general solution.

OpenStudy (experimentx):

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