Question

Finding the complex roots of an equation.

Answer 1

I have the complex roots.

Answer 2

\[\frac{-7\pm i\sqrt{159}}{8}\] ?

Answer 3

No I got (
-4(+/-)srt40*i)/8

Answer 4

isn't that an euler equation?

Answer 5

Yeah it's an Euler-Cauchy equation

Answer 6

@mukushla I was going through notes and I noticed this.

Answer 7

Do you think I can just sub in my roots.

Answer 8

u have \[t^2 x''+2tx'+\frac{13}{4}x=0\]letting \(t=\ln y\) gives\[x_y''+x_y'+\frac{13}{4}x_y=0\]am i right?

Answer 9

Yes. I didn't divide each term by 4 though

Answer 10

you have 4x^2+4z+13=0

Answer 11

Used the qradratic equation then.

Answer 12

yeah...

Answer 13

it gives
\[\frac{-4\pm8i \sqrt{3}}{8}=-\frac{1}{2}\pm i\sqrt{3}\]

Answer 14

Crap, small mistake. So Do I just sub that into the formula I posted

Answer 15

@mukushla how did you simplify down to iroot3?