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OpenStudy (anonymous):
Finding the complex roots of an equation.
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OpenStudy (anonymous):
OpenStudy (anonymous):
I have the complex roots.
OpenStudy (anonymous):
\[\frac{-7\pm i\sqrt{159}}{8}\] ?
OpenStudy (anonymous):
No I got ( -4(+/-)srt40*i)/8
OpenStudy (anonymous):
isn't that an euler equation?
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OpenStudy (anonymous):
Yeah it's an Euler-Cauchy equation
OpenStudy (anonymous):
@mukushla I was going through notes and I noticed this.
OpenStudy (anonymous):
Do you think I can just sub in my roots.
OpenStudy (anonymous):
u have \[t^2 x''+2tx'+\frac{13}{4}x=0\]letting \(t=\ln y\) gives\[x_y''+x_y'+\frac{13}{4}x_y=0\]am i right?
OpenStudy (anonymous):
Yes. I didn't divide each term by 4 though
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OpenStudy (anonymous):
you have 4x^2+4z+13=0
OpenStudy (anonymous):
Used the qradratic equation then.
OpenStudy (anonymous):
yeah...
OpenStudy (anonymous):
it gives \[\frac{-4\pm8i \sqrt{3}}{8}=-\frac{1}{2}\pm i\sqrt{3}\]
OpenStudy (anonymous):
Crap, small mistake. So Do I just sub that into the formula I posted
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OpenStudy (anonymous):
@mukushla how did you simplify down to iroot3?
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