Question

one positive number is two more than another. The sum of there squares is 34. Find the smaller number

Answer 1

one number is x, the other is x +2.
x + (x+2)^2 = 34
solve for x

Answer 2

its actually \[x^{2}+(x+2)^{2}=34\]

Answer 3

yepp...typo error

Answer 4

expand (x+2)^2

Answer 5

2x^2 +4x + 4 = 34

Answer 6

or x ^2 +2x -15 = 0

Answer 7

(x +5 )(x - 3) = 0

Answer 8

\[x^2+(x^2+4x+4)=34\]now combine like terms\[2x^2+4x+4=34\]now move the 34 over and factor to solve for x\[2x^2+4x-30=0\]

Answer 9

x = -5 or x = 3

Answer 10

sandy is correct! :)

Answer 11

thanks!