How many combinations exist for the letters m, n, o, p, and q taken 3 at a time? I would have thought it would have been 3! giving me 6, but that's not it.. Help? Thanks!
There are 5 letters total So there are 5 choices for the first slot 5-1 = 4 choices for the second slot and 5-2 = 3 choices for the third slot
10
Oh, right! So I do 5*4*3 giving me 60, right?
Which means that there are 5*4*3 = 20*3 = 60 possible ways to choose 3 letters from the 5 total
BUT that's if order matters Since order does not matter and something like mno mon nmo nom omn onm are all the same, then you've over counted by a factor of 3! =3*2*1 = 6
So you have to divide the count of 60 by 6 to get the final answer of 60/6 = 10 So there are 10 ways to choose three items from the list of five total where order doesn't matter
Ohhh, right. I forgot that combinations are different.. But thank you :)
yes if they specifically said "permutation", then order would matter
Oh right. Those darned specifics.. :P
sadly it gets confusing because a combination lock is really a permutation lock (at least to a mathematician)
That's beyond me.. Lol.
yeah it takes a while to get a good grasp of it
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