Question

What is the quotient of t^2-16/6t ÷2t+8/t-4 ?

Answer 1

\[
\frac{t^2-16}{6t} ÷\frac{2t+8}{t-4}\\
\frac{t^2-16}{6t} \frac{t-4}{2t+8}\\
\frac{(t -4)(t+4)}{6t} \frac{t-4}{2(t+4)}\\

\]
Can you finish it from here?

Answer 2

i got t^2-8t+16/12t but i know it is either a or b:

A) t^2-8t+16/12t, t ≠ −4, 0, 4
B) t^2-8t+16/12t, t ≠ 0, 4

which do you think?

Answer 3

I will say A. since the the fraction or its variants are not defined for t=-4,0,4

Answer 4

okay, thank you