http://www.wolframalpha.com/input/?i=y%3D%282cos+3x%29-1+ What points does the graph cross the x-axis?
it crosses the x-axis when y=0
so solve\[0=2\cos(3x)-1\]for x
so yeah, the answer is on there but why don't you try to do this without wolfram since you obviously aren't learning much from that site?
Well I am, it's just faster :/ Thank you though
Oh wait, can you please confirm? The absolute max is 1 and the absolute min is -3?
@TuringTest
Hello? You there?
sorry I was afk
max/min is when the derivative=0 so what is the derivative of this function?
I'm not sure :/
are you in calculus yet?
Nope
well what are the max and min values that y can be? (look at the graph, what is the highest/lowest it goes?)
oh you have it already, but those are not absolute max's or mins because they reoccur
absolute max/mins are like the highlander: "there can be only one" hence there is no absolute max or min on your graph, just a infinitely many relative ones
http://www.wolframalpha.com/input/?i=y%3D%282cos+3x%29-1+ So for this graph there are NO absolute maximum or minimum?
are you given an interval, or are you talking about the whole graph?
The whole graph
I want to say then the answer is "no" because of what I said earlier, but now I am starting to doubt myself and am looking for a formal definition of absolute max and min values one sec plz
Oh o.k. No problem, thank you so much
okay I was quite wrong, good thing I double-checked: "A function has a global (or absolute) maximum point at x∗ if f(x∗) ≥ f(x) for all x. Similarly, a function has a global (or absolute) minimum point at x∗ if f(x∗) ≤ f(x) for all x." so because we have \(\le,\ge\) and not \(<,>\) so there can be more than one, and they are what you said they are :)
Oh cool! Thanks so much for double checking because I wasn't even for sure myself. I appreciate your help, time, and patience :)
thanks for forcing me to learn something if you hadn't pressed me to be sure I might have kept telling people the wrong thing :P
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