Use the concept of slope to find t such that the three points are collinear: (-6,1), (1,t), (10,5)

Question

lgbasallote · Answer

the equation for slope is $$\huge \frac{y_2- y_1}{x_2 - x_1}$$
if they are all colinear that means their slopes are the same so$$\huge \frac{t-1}{1 - (-6)} = \frac{5-t}{10-1} = \frac{5-1}{10 - (-6)}$$
does that help?

lgbasallote · Answer

@EnergizedStudent15 you there?

anonymous · Answer

but yes this really does help! Alot! The only thing I'm confused about is answering it :/

lgbasallote · Answer

here's what you do...
$$\huge \frac{t-1}{1-(-6)} = \frac{5-1}{10-(-6)}$$
simplify those two sides..you   should get an "algebra" situation

anonymous · Answer

Yea......... ;^-^

anonymous · Answer

so from there it's pretty much cross multiplication right?

lgbasallote · Answer

yup

anonymous · Answer

but why is the $$5-t/10-1$$ crossed out?

lgbasallote · Answer

well you can use that too...it's just that an equation only consists of two parts..left side and right side...so i picked two from the three and equated them

anonymous · Answer

ohhhh okay.