Question

o

Answer 1

So I know I am supposed to take the derivative of y and put that on top and x on the bottom but I don't know what values to plug in after that

Answer 2

\[
\frac {y'(0)}{x'(0)}
\]

Answer 3

So that would mean 0 on the top. So it would equal 0?

Answer 4

yes

Answer 5

Is there ever a situation where I would have plugged in the pi^2 +1?

Answer 6

No. They gave you the point \( (0, \pi^2 +1)\) to notice that you have to
replace t by 0 in x(t) and y(t)