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OpenStudy (anonymous):
Example?
OpenStudy (anonymous):
ln(2) = 0.693
e^0.693 = 2
OpenStudy (anonymous):
My example is e^x+5/e^5=3 and I have to work it out but didn't know what e equalled. Thank you!!!
OpenStudy (anonymous):
Well, 5/e^5 = 0.0337
so you want x = ln(3 - 0.0337)
OpenStudy (lgbasallote):
actually....there's a simpler way..
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OpenStudy (lgbasallote):
\[\huge \frac{e^{x+5}}{e^5} \implies e^{x + 5 - 5}\]
do you agree? @calchelp101 ? this is algebra..
OpenStudy (anonymous):
Thank you! So would it now be e^x because it would cancel?
OpenStudy (anonymous):
sorry of course
e^x+5/e^5= e^x
OpenStudy (lgbasallote):
yup
OpenStudy (lgbasallote):
so \[\huge e^x = 3\]
now use ln
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OpenStudy (anonymous):
You both are the best! Thank you so much! If you don't mind, can I ask one more question: I now have e^x=3 Should it be left like that or multiply 3 by 1/x?
OpenStudy (anonymous):
Oh, okay! Thanks!
OpenStudy (lgbasallote):
haha =)) guess that was answered quick
OpenStudy (anonymous):
does ln cancel e?
OpenStudy (lgbasallote):
yup
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OpenStudy (lgbasallote):
...well it depends on what you mean
OpenStudy (lgbasallote):
can you show me what you're attempting to do?
OpenStudy (anonymous):
Sure. I have e^x=3 so would I have x=3(ln) after applying?
OpenStudy (anonymous):
So x=1.0986?
OpenStudy (lgbasallote):
x = ln (3) haha
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OpenStudy (lgbasallote):
did they tell you to give exact value?
OpenStudy (anonymous):
They didn't specify so I was going to give both.
OpenStudy (lgbasallote):
oh i see...that value is right
OpenStudy (anonymous):
Thank you so much! You are a lifesaver!
OpenStudy (lgbasallote):
haha welcome ^_^
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OpenStudy (anonymous):
Only if you have time, I have another ln problem that has been giving me trouble!
OpenStudy (lgbasallote):
sure
OpenStudy (lgbasallote):
what's the problem?
OpenStudy (anonymous):
ln(2x^6+3 square roots of x+8/(x-1)^4)
OpenStudy (lgbasallote):
\[\huge \ln \left(\frac{2x^6 + 3\sqrt{x+8}}{(x-1)^4} \right)\]
is this the problem?
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OpenStudy (anonymous):
Yes
OpenStudy (lgbasallote):
and you're supposed to.....expand it?
OpenStudy (anonymous):
Yes and simplify
OpenStudy (lgbasallote):
if i were you i'll start with quotient law first
OpenStudy (anonymous):
So after I expand (x-1)^4 what should I do with the 3square roots of x+8?
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OpenStudy (lgbasallote):
nothing :D
OpenStudy (lgbasallote):
there is no expansion for \[\ln (a+b)\]
OpenStudy (anonymous):
Oh. Okay. On the bottom I have x^4-4x^3+8x^2-8x+4
OpenStudy (lgbasallote):
well...not exactly...
OpenStudy (lgbasallote):
this is not what i meant by expand...
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OpenStudy (anonymous):
You meant expand the ln?
OpenStudy (lgbasallote):
lol that's the objective isnt it?
OpenStudy (anonymous):
Well yes. haha
OpenStudy (lgbasallote):
so expand the ln
OpenStudy (lgbasallote):
use quotient law first
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