Question

use integration by parts: integral of (4x-12)e^(-8x) dx

Answer 1

\[\int (4x-12) e^{-8x}dx\]
u = 4x - 12
du = 4dx

dv = e^(-8x)
v = -e^(-8x)/8

\[uv - \int vdu\]
\[\implies -\frac{(4x-12)e^{-8x}}{8} - \int -\frac{4e^{-8x}}{8}dx\]
does that help?

Answer 2

@austin84 you there?

Answer 3

thank you.. it did help. The book says that the final answer is (-x/2+23/16)e^(-8x)+c.do I need to repeat the integration by parts to get this answer?

Answer 4

no..you dont need to do another integration by part...that laqst integral is a perfect integral