Question

help with backwards intergral derrivate

elvalate the following intergate sign y=( x^2+3x+5) dx

Answer 1

use the rule dx=x+c
the d/dx is 1x+3) DX

Answer 2

so there fore we use x^2 dx = 1/n+1 x^n+1 +C right?

Answer 3

yes right

Answer 4

is this your question?\[y=\int (x^2+3x+5)\text dx\]

Answer 5

yes sir

Answer 6

yes apply \[\int ax^n=\frac{ax^{n+1}}{n+1}+c\]

Answer 7

so do I use D/DX to apply to this or whole problem again that is where I am lost..

Answer 8

\[y=\int (x^2+3x+5)\text dx=\frac{x^{2+1}}{2+1}+\frac{3x^{1+1}}{1+1}+\frac {5x^{0+1}}{0+1}+{c}\]

Answer 9

okay I thought you did d/DX and than use that

Answer 10

not the problem without finding D/DX what am missing hrere??

Answer 11

i dont know what you mean

Answer 12

I did the der first than tried to apply that form to it

Answer 13

y=1x+3 D/DX

Answer 14

huh/?
if \[f(x)=x^2+3x+5\]\[f'(x)=2x+3\], but i dont know why you are differentiating

Answer 15

opps 2x not 1x. That is what I was asking do you need to differentate before using that formula

Answer 16

differentiating is kinda like the opposite to integrating,
like + is oppositse to -
and x is opposite to \(\div\),

Answer 17

if the question is an integration, differentiating wont help much

Answer 18

but once you have integrated ,
you could check if differentiating get you back to the original question,

Answer 19

okay so the whole problem must used and be plugged in as such.

Answer 20

for every x I use x^2 and so on.

Answer 21

for example
\[y=\int10x\text dx=\frac{10x^2}{2}+c=5x^2+c\]

\[\frac{\text dy}{\text dx}=\frac{\text d}{\text dx}(5x^2+c)=2\times5x=10x\]

\[\text dy=10x\text dx\]
\[\int\text dy=\int10x\text dx\]\[y=\int10x\text dx\]

Answer 22

so pretty much you sub in all values for letters with in the formula and do the intergation from that point right?

Answer 23

what do you get?

Answer 24

how do you use the equation function on this board??

Answer 25

i dont use the equation tool ive been typing the \(\LaTeX\) by hand
for example type

y=\int10x\text dx=\frac{10x^2}{2}+c=5x^2+c

with \[\[ \]\] around the whole expression produces

\[y=\int10x\text dx=\frac{10x^2}{2}+c=5x^2+c\]

Answer 26

so in plugging in the rule i have x^2 dx=1/5+1 x^2 +c did sub right here?

Answer 27

i dont understand what you have done

Answer 28

i sub in the values for what the formula called for

Answer 29

what sucks here I have a TI 92 but no batteries until Wed or Th so I can't do this

Answer 30

\[y=\int (x^2+3x+5)\text dx\]\[=\int x^2\text dx+\int3x\text dx+\int5\]\[=\frac{x^{2+1}}{2+1}+\frac{3x^{1+1}}{1+1}+\frac {5x^{0+1}}{0+1}+{c}\]

Answer 31

okay how do what goes where that is what I am missing here..

Answer 32

* there should be a dx after the 5

Answer 33

there is.

Answer 34

you confuse me @godorovg

Answer 35

I am asking how to know what is sub in and where when using the perfect power rule for intergrals

Answer 36

what substitution are you talking about ?

Answer 37

you have the this rule x^2 dx=1/n+1 x^n+1 +c now I do I use this with y=x^2 +3x+5 that is my question.

Answer 38

help with where 3x and the 5 goes with this and why?