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Chemistry 15 Online
OpenStudy (anonymous):

Determine the number of grams of NaCl necessary to make up 100 mL of a 0.10 M solution. 0.017 g 0.58 g 1.7 g 58 g

OpenStudy (anonymous):

100 ml 0.10 M solution has 0.10*0.1 = 0.01 moles of NaCl. 0.01 moles of NaCl is required to make the solution. So the weight of NaCl required(no. of moles * molar mass) is 0.01*58 = 0.58 grams. Option b) 0.58 grams.

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