Question

help me with this please. i am quite confused here. thank you.

Answer 1

determine x and v.

Answer 2

that's all the info?

Answer 3

yes.

Answer 4

it's to be solved using KCL and KVL

Answer 5

in the pix you're given currents thru two parallel branches : \( I1 \ \& I2 \)

Answer 6

do u see two loops, one loop current is I1,
other loop current is I2

right ?

Answer 7

apply KVL to I1 loop,

\(240 = 100I1 + xI1 \)

\(x = \frac{240-100I1}{I1} \)

Answer 8

you can find v by finding the node voltages on either ends and subtracting them

Answer 9

V on top node = 240-100I1
V on bottom node = 240 - 200I2

\(V = (240-100I1) - (240-200I2)\)

\( = 200I2-100I1 \)

Answer 10

is the current that passes through 100ohms the same as the current passing through x?

Answer 11

yes they are in series.
the circle shown vertically with V letter is just a Voltmeter.

Answer 12

really? aw, thank you for that info :)

Answer 13

yeah thats just a measuring device. you can visualize the circuit, by thinking its not present if it helps.. .

Answer 14

i still cant get x and v. :(

Answer 15

i need more equations.

Answer 16

nope.
you cant get x & v numerically.
you must leave them as expressions in I1, and I2

Answer 17

why? insufficient values?

Answer 18

I1, and I2 are the given currents right ?

Answer 19

yes.

Answer 20

they came from problem. you didnt create them right ?

Answer 21

so its okay to leave x & v in terms of I1 & I2

Answer 22

and you cant get the x & v here for sure in any other terms.

Answer 23

ok. :) thanks again. :)

Answer 24

again. you can find I2 numerical value,
\(I2 = \frac{240}{200+150}\)

but you can never find I1 numerical value, as it depends on x.
\(I1 = \frac{240}{100 + x}\)


so the question is just asking you to GET x & v values in terms of the given I1, I2 values. hope it is clear...

Answer 25

yes. it's clear to me now.

Answer 26

:D